Q. 74.6( 5 Votes )
If the sum of thr A. 13
B. 9
C. 21
D. 17
Answer :
Let 3 consecutive terms A.P is a –d, a, a + d. and the sum is 51
So, (a –d) + a + (a + d) = 51
3a –d + d = 51
3a = 51
a = 17
The product of first and third terms = 273
So, (a –d) (a + d) = 273
a2 –d2 = 273
172 –d2 = 273
289 –d 2 = 273
d2 = 289 –273
d2 = 16
d = 4
Third term = a + d = 17 + 4 = 21
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