Given:Mean= 2Variance=1P(x>1)=?P(x>1)=1-p(x1)= 1-[p(x=0)+p(x=1)]=1-[ 11qn +npqn-1]2(1-p)=1=qnp=2n=4

Q. 75.0( 2 Votes )

If the mean and v

Answer :

Given:

Mean= 2

Variance=1

P(x>1)=?

P(x>1)=1-p(x1)

= 1-[p(x=0)+p(x=1)]

=1-[ 11qⁿ +npq^n-1]

2(1-p)=1

np=2

n=4

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