Mark against the A. x + 2y – 3z = 14

B. x – 2y + 3z = 12

C. x – 2y – 3z = 14

D. None of these

Given: P(1, 2, -3) is a point on the plane. OP is perpendicular to the plane.

Explanation:

Let equation of plane be ax + by + cz = d … (1)

Substituting point P,

⇒ a + 2b -3c = d … (2)

Since OP is perpendicular to the plane, direction ratio of the normal is (1, 2, -3)

Substituting in (2)

1 + 4 + 9 = d

d = 14

Substituting the direction ratios and value of ‘d’ in (1), we get

x + 2y – 3z = 14

Therefore equation of plane is x + 2y – 3z = 14