# If A = <spa

As, A =

A2 =

Using matrix multiplication method we can write it as-

A2 =

A2 =

A2 – 5A + 4I =

A2 – 5A + 4I =

A2 – 5A + 4I =

A2 – 5A + 4I =

Now we need to find X such that -

A2 – 5A + 4I + X = 0

X =

X =

OR

As we know that transpose of a matrix is given by interchanging rows with respective columns.

A’ = AT =

Inverse of any matrix(say B) is given by:

B-1 =

Assume, B =

Determinant of B = |B| =

|B| = 1(-1-8)-0(-2-6)-2(-8+3)

|B| = -9+10 = 1

Adjoint of a matrix is given by the transpose of cofactor matrix.

Co-factor matrix of B =

(A’)-1 =

Hence,

(A’)-1 =

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