# If A = <spa

As, A = A2 = Using matrix multiplication method we can write it as-

A2 = A2 = A2 – 5A + 4I = A2 – 5A + 4I = A2 – 5A + 4I = A2 – 5A + 4I = Now we need to find X such that -

A2 – 5A + 4I + X = 0 X = X = OR

As we know that transpose of a matrix is given by interchanging rows with respective columns.

A’ = AT = Inverse of any matrix(say B) is given by:

B-1 = Assume, B = Determinant of B = |B| = |B| = 1(-1-8)-0(-2-6)-2(-8+3)

|B| = -9+10 = 1

Adjoint of a matrix is given by the transpose of cofactor matrix.

Co-factor matrix of B = adj(B) = (A’)-1 = Hence,

(A’)-1 = Rate this question :

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