# If 4x + 6y = 3xy and 8x + 9y = 5xy thenA. x = 2, y = 3B. x = 1, y = 2C. x = 3, y = 4D. x = 1, y = – 1

We have,

4x + 6y = 3xy …(i)

8x + 9y = 5xy …(ii)

Now, dividing (i) and (ii) by xy we get:

…(iii)

Also, …(iv)

Now, multiplying (iii) by2 and then subtracting it from (iv) we get:

x = 3

Now, substituting the value of x in (iii) we get:

y = 4

Hence, option C is correct

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