px(x-3) + 9=0
px2-3px + 9=0
This is a quadratic equation of form ax2 + bx + c=0
Where a=p, b=-3p, c=9
For equal roots, D=0
Substituting the values of a,b and c
There are two possible values of p, p=0 and p=4
We neglect p=0 as on putting p=0; the equation does not remain quadratic.
∴ p=4 is our required answer.
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