Q. 74.4( 10 Votes )

# Find the value of

Answer :

Given,

Roots of the equation are equal,

px(x-2) + 6 = 0

px2 – 2px + 6 = 0 p≠0

Let’s take

a = p

b = -2p

c = 6

b2 – 4ac = 0

(-2p)2 – 4(p)(6) = 0

4p2 – 24p = 0

4p(p – 6) = 0

4p = 0 or p – 6 = 0

p = 0 or p = 6

But p cannot be equal to 0

According to the Standard form of quadratic equation;

ax2 + bx + c = 0

a ≠ 0

p = 6

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