# Find the value of

Given,

Roots of the equation are equal,

px(x-2) + 6 = 0

px2 – 2px + 6 = 0 p≠0

Let’s take

a = p

b = -2p

c = 6

b2 – 4ac = 0

(-2p)2 – 4(p)(6) = 0

4p2 – 24p = 0

4p(p – 6) = 0

4p = 0 or p – 6 = 0

p = 0 or p = 6

But p cannot be equal to 0

According to the Standard form of quadratic equation;

ax2 + bx + c = 0

a ≠ 0

p = 6

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Glimpses of India39 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Every odd integerRD Sharma - Mathematics

Every even integeRD Sharma - Mathematics

A number when divRS Aggarwal - Mathematics

If n is an odd inNCERT - Maths Exemplar

Show that the squMathematics - Board Papers

The remainder wheRD Sharma - Mathematics

Euclid’s divisionRS Aggarwal - Mathematics