Q. 75.0( 2 Votes )

Find the equation of the tangent and the normal to the following curves at the indicated points:
y2 = 4ax at (x1, y1)  (CBSE 2012)

Answer :

The figure is below:

finding slope of the tangent by differentiating the curve




m(tangent) at (x1, y1) =


normal is perpendicular to tangent so, m1m2 = – 1


m(normal) at (x1, y1) =


equation of tangent is given by y – y1 = m(tangent)(x – x1)



equation of normal is given by y – y1 = m(normal)(x – x1)


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