Q. 75.0( 2 Votes )

# Find the equation of the tangent and the normal to the following curves at the indicated points:

y^{2} = 4ax at (x_{1}, y_{1}) *(CBSE 2012)*

*(CBSE 2012)*

Answer :

The figure is below:

finding slope of the tangent by differentiating the curve

m(tangent) at (x_{1}, y_{1}) =

normal is perpendicular to tangent so, m_{1}m_{2} = – 1

m(normal) at (x_{1}, y_{1}) =

equation of tangent is given by y – y_{1} = m(tangent)(x – x_{1})

equation of normal is given by y – y_{1} = m(normal)(x – x_{1})

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