# Find the equation of the tangent and the normal to the following curves at the indicated points:y2 = 4ax at (x1, y1)  (CBSE 2012)

The figure is below:

finding slope of the tangent by differentiating the curve

m(tangent) at (x1, y1) =

normal is perpendicular to tangent so, m1m2 = – 1

m(normal) at (x1, y1) =

equation of tangent is given by y – y1 = m(tangent)(x – x1)

equation of normal is given by y – y1 = m(normal)(x – x1)

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