[CBSE 2016]Answer :
Given:
plane 1: 2x - 3y + 6z – 4 = 0 and
plane 2: 6x - 9y + 18z + 30 = 0
General form for equation of plane is given by ax + by + cz + d
Now comparing the co - efficient of x, y and z for both the planes
Ratio of co - efficient of x = 
The ratio of the coefficient of y = 
The ratio of the coefficient of z = 
Now since all the ratios are equal, we can say that both the planes are parallel to each other
Arbitrarily selecting a point which lies on plane 1, let’s say (x1, y1, z1) which is (2, 0, 0)
Now the distance between the planes is given by
Formula: 
Substituting the values in the above equation
Hence, the distance between the given planes is 2 units.
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