Q. 75.0( 1 Vote )
Draw an isosceles right triangle of hypotenuse 4 centimetres.
Answer :
1) Draw a line BC 4 cm.
2) At B, draw ∠XBC = 45°
3) At C, draw ∠YCB = 45°
BX and CY intersect each other at A. and ΔABC is required triangle,
Also,
In ΔABC
∠B = ∠C = 45°
Therefore, AB = AC [i.e. ABC is isosceles]
And By angle sum property of triangle,
∠A + ∠B + ∠C = 180°
⇒ ∠A + 45 + 45 = 180
⇒ ∠A = 90°
Hence, ABC is isosceles.
Rate this question :
Quiz | Testing Your Knowledge on Circles32 mins
Important Questions on Circles46 mins
Quiz | Imp. Qs. on Circle35 mins
Smart Revision | Circles44 mins
Quiz | Imp. Qs. on Circles37 mins
RD Sharma | Important Questions on Circles36 mins
Short Cut Trick to Find Area of Triangle43 mins
Tangent from an External Point54 mins
RD Sharma | Most Important Questions of Circles35 mins
RD Sharma | Imp Qs Discussion on Area Related With Circles41 mins
A 2.6 metres long rod leans against a wall, its foot 1 metre from the wall. When the foot is moved a little away from the wall, its upper end slides the same length down. How much farther is the foot moved?
An isosceles triangle has to be made like this
The height should be 2 metres less than the base. What should be the length of its sides?
Kerala Board Mathematics Part-1Draw an isosceles right triangle of hypotenuse 4 centimetres.
Kerala Board Mathematics Part-1Draw an equilateral triangle of height 3 centimetres.
Kerala Board Mathematics Part-1The vertices of a triangle are the points with coordinates (3, 5), (9, 13), (10, 6). Prove that the triangle is isosceles. Calculate is area.
Kerala Board Mathematics Part-2Prove that in any parallelogram, the sum of the square of all sides is equal to the sum of the squares of the diagonals.
Kerala Board Mathematics Part-2