Q. 75.0( 2 Votes )

# Determine the equ

Answer :

(i) We can see in the graph that the graph passes through the points (3, 8) and (-3, -3)

Now, let (x1, y1) = (3, 8) and (x2, y2) = (-3,-3)

Now the equation of the line passing through (x1, y1) and (x2, y2) is given by-

⇒ 6y-48 = 11x-33

⇒ **6y = 11x + 15**

(ii) We can see in the graph that the graph passes through the points (-4, 2) and (12, -3)

Now, let (x1, y1)=(-4, 2) and (x2, y2)=(12,-3)

Now the equation of the line passing through (x1,y1) and (x2,y2) is given by-

⇒ 16y – 32 = - 5x - 20

⇒ **16y = - 5x + 12**

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