Q. 73.7( 3 Votes )

Construct a triangle ABC with perimeter 10 cm and each base angle is of 45°.

Answer :

                                               
Steps of Construction
1. Draw a ray PX and cut off a line segment PQ = 10 cm from it.
2. At P, construct ∠YPQ = 22° (45° )
3. At Q, construct ∠ZQP = 22°(45° )
4. Draw the perpendicular bisector of AP intersecting PQ at a point B.
5. Draw the perpendicular bisector of AQ intersecting PQ at a point C.
6. Join AB and AC.
Then, ABC is the required triangle.

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