Answer :

Steps of Construction

1. Draw a ray PX and cut off a line segment PQ = 10 cm from it.

2. At P, construct ∠YPQ = 22° (45° )

3. At Q, construct ∠ZQP = 22°(45° )

4. Draw the perpendicular bisector of AP intersecting PQ at a point B.

5. Draw the perpendicular bisector of AQ intersecting PQ at a point C.

6. Join AB and AC.

Then, ABC is the required triangle.

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