Q. 75.0( 1 Vote )

# Consider the foll

To find median class,

Assume Σfi = N = Sum of frequencies,

fi = frequency of class intervals

and Cf = cumulative frequency

Lets convert this data into exclusive type of data.

So, N = 57

N/2 = 57/2 = 28.5

The cumulative frequency just greater than (N/2 = ) 28.5 is 38, so the corresponding median class is 11.5 - 17.5.

Upper limit of this median class = 17.5

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