Answer :

Given.

Distance = 100km

If average speed been increased by 10 kilometres per hour, I could have reached here one hour earlier

Formula used.

Average speed =

Let the sum of time taken be x

Average speed =

New average speed = average speed + 10

+ 10

10x = (x–1)(10 + x)

10x = 10x + x^{2}–10–x

x^{2}–x–10 = 10x–10x = 0

x^{2}–x–10 = 0

As comparing eq to ax^{2} + bx + c = 0

x =

x = = =

As √41 is greater than 1

∴ time cannot get negative

Hence; time is hours

Average speed =

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