Given: Height of the window from the ground = 8 m
Length of the ladder = 10 m
To find: Distance of the foot of the ladder from the base of the wall.
Consider the following diagram corresponding to the question.
Here, AB = Height of the window form the ground = 8 m
AC = Length of the ladder = 10 m
BC = Distance of the foot of the ladder from the base of the wall
Now, in ∆ ABC,
By Pythagoras theorem, we have
AC2 = AB2 + BC2
⇒ BC2 = AC2 – AB2
⇒ BC2 = (10)2 – (8)2 = 100 – 64 = 36
⇒ BC = √36 = 6 m
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