Q. 68

# In figure, m and n are two plane mirrors parallel to each other. Show that the incident ray CA is parallel to the reflected ray BD.

Given: m and n are parallel to each other.To prove: ray BD || ray CA.Proof:BQ is the normal to the reflecting surface. ⇒ BQ ⊥ n.Similarly, AP is the normal to the reflecting surface.⇒ AP⊥ m.⇒ Since m || n.AP || BQ.  ⇒ ∠QBA = ∠BAP (Alternate angles are equal)∴ 2∠QBA = 2∠BAP     ∠DBA = ∠BAC (The angle of incidence = The angle of reflection)ray BD || ray CA ( Alternate angles are equal ).

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