# The height of the

Given: The height of the conical tent is 14m and its floor area is 346.5m2.

Canvas of width 1.1m

Surface area of the tent is: πrl

Let be the Surface area of the cone.

Area of the floor is : πr2= 346.5 m2

πr2= 346.5

r2 = =

r = √( ) =

l = √(h2 + r2) (here l is the slant height and h , r are height and radius respectively of cone)

l = √(142 + ()2) = √(196 + ) = √ =

S = πrl = π × =

Area of the canvas required to cover the tent is: m2

l × b = m2 (here l is length and b is breadth or width of the canvas)

l × 1.1 = ( width of the canvas is 1.1m)

l = = 525m

Length of the canvas required to cover the tent is 525m

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