Answer :

Given: The height of the conical tent is 14m and its floor area is 346.5m2.


Canvas of width 1.1m


Surface area of the tent is: πrl


Let be the Surface area of the cone.


Area of the floor is : πr2= 346.5 m2


πr2= 346.5


r2 = =


r = √( ) =


l = √(h2 + r2) (here l is the slant height and h , r are height and radius respectively of cone)


l = √(142 + ()2) = √(196 + ) = √ =


S = πrl = π × =


Area of the canvas required to cover the tent is: m2


l × b = m2 (here l is length and b is breadth or width of the canvas)


l × 1.1 = ( width of the canvas is 1.1m)


l = = 525m


Length of the canvas required to cover the tent is 525m

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