Q. 634.2( 5 Votes )

# If P (-5, -

Answer :

Let P(−5,−3); Q(−4,−6); R(2,−3) and S(1,2) be the vertices of quadrilateral PQRS.

Area of the quadrilateral PQRS = Area of ∆PQR + Area of ∆PSR

Area of the triangle having vertices (x1,y1), (x2,y2) and (x3,y3)

= |x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|

Area of ∆PQR = |− 5( − 6 + 3 ) − 4( − 3 + 3 ) + 2( −3 + 6) |

= |15 + 0 + 6|

= sq. units

Area of ∆PSR = | − 5( 2 + 3 ) + 1( − 3 + 3 ) + 2( − 3 2) |

= | − 25 + 0 10 |

= sq. units

Area of the quadrilateral PQRS = + = 28 sq. units

Hence, the area of the quadrilateral is 28 sq. units.

(given answer is wrong, its not 13, it is 28 )

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Doubt Session47 mins  Basics of Coordinate Geometry53 mins  Distance Formula52 mins  Section Formula53 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 