Answer :

We are given that,


We need to find the value of (x + y + z).


We know by the property of matrices,



This implies,


a11 = b11, a12 = b12, a21 = b21 and a22 = b22


We have,



Therefore,


xy = 8 …(i)


4 = w …(ii)


z + 6 = 0 …(iii)


x + y = 6 …(iv)


We have the equations (i), (ii), (iii) and (iv).


We just need to find the values of x, y and z. So,


From equation (iii),


z + 6 = 0


z = -6


Now, let us find (x + y + z).


Substituting z = -6 and the value of (x + y) from equation (iv),


x + y + z = (x + y) + z


x + y + z = 6 + (-6)


x + y + z = 6 – 6


x + y + z = 0


Thus, the value of (x + y + z) is 0.


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