Answer :

**Given:** ΔABC ~ΔDEF

area (Δ ABC) = 16 cm^{2}

area (Δ DEF) = 25 cm^{2}

BC = 2.3 cm

**To find:** The length of EF.

**Theorem Used:**

**Area of similar triangle:**

The ratio of the areas of two similar triangles are equal to the ratio of the squares of any two corresponding sides.

**Explanation:**

Since, ΔABC ~ΔDEF

Then by area of similar triangle theorem,

By taking square root,

EF = 2.875cm

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