Q. 64.2( 13 Votes )

Tickets num

Answer :

Concept Used:



Numbers multiple of 3: 3, 6, 9, 12, 15, 18


Explanation:


Total numbers of elementary events are = 20


Let E be the event of drawing a multiple of 3


The favourable outcomes are: 3, 6, 9, 12, 15, 18


Total numbers of favourable outcomes are = 6


P (multiple of 3) = P (E) = 6/20 =3/10


Hence, the probability of getting a multiple of 3 is 3/10.


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