Answer :
Total number of ways in which the letters can be put = 3! = 6
Suppose, out of the three letters, one has been put in the correct envelope.
This can be done in 3C1 ways. (3 ways)
Now, out of three, if two letters have been put in the current envelope, then the last one has been put in
the correct envelope as well. This can be done in 3C3 ways. (1 way)
Number of ways = 3 + 1 = 4
Number of ways in which no letter is put in correct envelope = 6 – 4 = 2
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