Answer :

If we are given the distance travelled(x) as a function of time, we can calculate velocity(v) and acceleration(a) by

and a

x(t)= t3 – 12t2 + 6t + 8

differentiating w.r.t. time, we get

Differentiating again w.r.t. time, we get


Given that a=0 6t-24=0 or t=4 units

v(4)=3×42 -24×4+6 =-42

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