Q. 65.0( 1 Vote )


Prove that:
(CBSE 2011)

Answer :

Taking ‘a’, ‘b’ and ‘c’ outside the determinant from 1st,2nd and 3rd column respectively


Taking ‘a’, ‘b’ and ‘c’ outside the determinant from 1st,2nd and 3rd row respectively


.


R1 R1 + R2 (i.e. Replacing 1st row by addition of 1st and 2nd row)



panding the determinant along 1st row



LHS = a2 b2 c2 × 2(1 - (-1)) = 4a2b2c2 = RHS


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