Q. 63.8( 12 Votes )

PQRS is a diamete

Answer :

Given,


Radius (OS) of the circle = 6 cm


Diameter (PS) of the circle = 12 cm


PQ, QR, and RS, three parts of the diameter are equal


So,


PQ = QR = RS = 4 cm


And


QS = 2 × 4 = 8 cm


So, Required perimeter;


= arc PS + arc QS + arc PQ


= π ×6 + π×4 + π×2



37.7 cm


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