Q. 64.2( 9 Votes )

Let m be the midpoint and u be the upper class limit of a class in a continuous distribution. The lower class limit of the class is
A. 2m – u

B. 2m + u

C. m – u

D. m + u

Answer :

We know that,

Mid-point = 1/2 (upper class limit + lower class limit)

m = 1/2 (upper class limit + lower class limit)

upper class limit = u (given)

u + lower class limit = 2m

lower class limit = 2m – u .

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