Answer :

Given that EGB=50°

Since, AB||CD and EF is a transversal,


GHD=EGB=50° (corresponding angles) ……….(1)


CHF=EGB=50° (alternate exterior angles)


AGH=GHD =50° (alternate interior angles)


Now, BGH+GHD=180° (co-interior angles)


BGH+50° =180° (from (1))


BGH=180°-50°


BGH=130°


GHC=BGH=130° (alternate interior angles)


AGE=GHC=130° (corresponding angles)


DHF=AGE=130° (alternate exterior angles)


Hence, GHD=50°, CHF=50°, AGH=50°, BGH=130°, GHC=130°, AGE=130° and DHF=130°


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