Answer :

(1) Radius of circle, r = 7cm

Area of circle,A_{C} = πr^{2}

⇒ A_{C} = 154 sq. cm

∴ area of circle is 154 sq.cm

(2) Angle subtended by the arc = 60°

As we know,

⇒ A(O- MBN) = 25.7 sq. cm

(3) A(O- MCN) = Area of circle – A(O – MBN)

⇒ Area(O – MCN) = A_{C} – 25.7

⇒ Area(O – MCN) = 154 – 25.7

∴ Area of major sector is 128.3 sq. cm

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