Answer :

We know that a perpendicular drawn from the center of a circle on its chord bisects

the chord.

So, AE = EB

In ΔACE and ΔBCE,

AE = EB

∠AEC = ∠BEC = 90°

CE = CE (common)

Δ ACE ≅ Δ BCE (By SAS congruence)

Therefore, AC = BC (by CPCT)

Hence proved that ABC is an isosceles triangle.

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