In Fig. given bel

Given that,

ABCD is rectangle

CD = 6 cm

AB = 6 cm (opp. sides of rectangle)

AD = 8 cm

We know that,

If a rectangle and a parallelogram are on the same base and between the same parallels, then the area of a triangle is equal to the half of parallelogram

Δ GEF and parallelogram ABCD are on the same base and between same parallels.

Area of parallelogram = Base × Height

Now,

Area Δ GEF = 1/2 × Area of ABCD

= 1/2 × AB × AD

= 1/2 × 6× 8

= 24 cm²

Hence,

Hence area Δ GEF is 24 cm².