Q. 65.0( 4 Votes )

In Δ ABC, if bisectors of ABC and ACB intersect at O angle of 120°, then find the measure of A.

Answer :


BOC + OBC + OCB = 180o

120o + B + C = 180o

(B + C) = 60o

B + C = 120o (i)


A + B + C = 180o

A + 120o = 180o [From (i)]

A = 60o

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