Q. 65.0( 2 Votes )

In Δ ABC B= C and ray AX bisects the exterior angle DAC. If DAX =70°, then ACB =
A. 35°

B. 90°

C. 70°

D. 55°

Answer :

AX bisects DAC

CAD = 2 * DAC

CAD = 2 * 70o

= 140o

By exterior angle theorem,

CAD = B + C

140o = C + C (Therefore, B = C)

140o = 2C

C = 70o

Therefore, C = ACB = 70o

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