Q. 63.9( 8 Votes )
A. Draw the given square ABCD.
B. Draw the diagonal DB of square ABCD.
C. Draw a parallel line through point C to diagonal DB of square ABCD which intersects at E produced AB.
D. CE||DB. ΔADE is the required triangle.
∆DCB = ∆DBE (on same base DB and between same parallels DB and CE)
∴ ∆DCB = ∆DBE
∆ABD + ∆DCB = ∆DBE + ∆ABD (adding area of ∆ABD on both sides)
∴ square ABCD = ∆ADE
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