Q. 64.5( 4 Votes )

# Find the vector equation of the plane with intercepts 3, -4 and 2 on x, y and z-axis respectively.[CBSE 2016]

Given: intercepts of plane on x, y and z-axis are 3, -4 and 2 respectively

To find: vector equation of the plane

Formula used:

The intercept form of the plane with intercepts a, b and c on x, y and z-axis respectively is given by,

Here a = 3, b = -4 and c = 2

Therefore,

4x – 3y + 6z = 12

Hence, the vector equation of the plane is,

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