Q. 64.5( 4 Votes )
Find the vector equation of the plane with intercepts 3, -4 and 2 on x, y and z-axis respectively.[CBSE 2016]
Answer :
Given: intercepts of plane on x, y and z-axis are 3, -4 and 2 respectively
To find: vector equation of the plane
Formula used:
The intercept form of the plane with intercepts a, b and c on x, y and z-axis respectively is given by,
Here a = 3, b = -4 and c = 2
Therefore,
⇒ 4x – 3y + 6z = 12
Hence, the vector equation of the plane is,
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