Q. 64.5( 4 Votes )

# Find the vector equation of the plane with intercepts 3, -4 and 2 on x, y and z-axis respectively.**[CBSE 2016]**

**[CBSE 2016]**

Answer :

**Given:** intercepts of plane on x, y and z-axis are 3, -4 and 2 respectively

**To find:** vector equation of the plane

**Formula used:**

The intercept form of the plane with intercepts a, b and c on x, y and z-axis respectively is given by,

Here a = 3, b = -4 and c = 2

Therefore,

⇒ 4x – 3y + 6z = 12

Hence, the vector equation of the plane is,

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