In a square of side say a cm, any diagonal divide the square into two right triangles of equal dimensions. Thus a2 + a2 = 102 ⇒ 2a2 = 100 ⇒ a2 = 50 a = 5 cm perimeter = 4a = 4×5 = 20 Perimeter of square = 20cm

Q. 64.0( 20 Votes )

Find the side and

Class 10th MHB - Mathematics Part-2 2. Pythagoras Theorem

Answer :

In a square of side say a cm, any diagonal divide the square into two right triangles of equal dimensions.

Thus a² + a² = 10²

⇒ 2a² = 100

⇒ a² = 50

a = 5 cm

perimeter = 4a

= 4×5

₌ 20

_{Perimeter of square =} 20_cm

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