Q. 64.7( 3 Votes )
Find the area of an isosceles triangle each of whose equal side is 13 cm and whose base is 24 cm.
Answer :
Given:
Side AB = Side AC = 13 cm
Base = 24 cm
In ∆ADC (right-angled),
DC = 12 cm
By Pythagoras theorem,
AD2 + DC2 = AC2
⇒ AD2 = AC2 - DC2
⇒ AD2 = 132 - 122
⇒ AD2 = 169 – 144 = 25
⇒ AD = 5 cm
Now,
Area of triangle = 1/2 × base × height
= 1/2 × BC × AD
= 1/2 × 24 × 5
= 60 cm2
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