# Find the area of an isosceles triangle each of whose equal side is 13 cm and whose base is 24 cm.

Given:

Side AB = Side AC = 13 cm

Base = 24 cm

DC = 12 cm

By Pythagoras theorem,

AD2 = 169 – 144 = 25

Now,

Area of triangle = 1/2 × base × height

= 1/2 × BC × AD

= 1/2 × 24 × 5

= 60 cm2

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