Answer :
Let 
Let f(x) = (1 - x2) sin x cos2x
f(-x) = (1 - (-x)2) sin(-x) cos2(-x)
= -(1 - x2) sin x cos2x
= - f(x)
Hence f(x) is an odd function.
Using 
if f(x) is an odd function, we get I = 0.
OR
Consider
,Let 
|x|=-x, if x<0
And |x|=x, if x≥0
Hence, 
= [-0 - (-1)] + [2 - 0]
= [0 + 1] + [2-0]
= 1 + 2
=3
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