Answer :

Let


Let f(x) = (1 - x2) sin x cos2x


f(-x) = (1 - (-x)2) sin(-x) cos2(-x)


= -(1 - x2) sin x cos2x


= - f(x)


Hence f(x) is an odd function.


Using if f(x) is an odd function, we get I = 0.


OR

Consider ,

Let


|x|=-x, if x<0


And |x|=x, if x≥0




Hence,

= [-0 - (-1)] + [2 - 0]

= [0 + 1] + [2-0]

= 1 + 2

=3

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