Answer :

Step 1: Draw a line segment AB = 4.2 cm.

Step 2: Taking A as center, draw an arc of radius 6.2 cm. Then, take B as center and draw an arc of radius 5 cm. These arcs will intersect at point C (say). Join AC and BC, such that AC = 6.2 cm and BC = 5 cm. Thus, ∆ABC is the required triangle.

Step 3: Draw a ray AX making acute angle with straight line AB to the opposite side of vertex C.

Step 4: Locate 3 points on ray AX, namely A _{ 1 } , A _{ 2 } and A _{ 3 } (since 3 is greater among 2 and 3) such that, AA _{ 1 } = A _{ 1 } A _{ 2 } = A _{ 2 } A _{ 3 } .

Step 5: Join BA _{ 3 } and then draw a line through A _{ 2 } such that it is parallel to BA _{ 3 } and intersects on AB at B’.

Step 6: Now draw a line through B’ such that it is parallel to BC and intersects on AC at C’.

∆AB’C’ is the required triangle with sides 2/3 of the corresponding sides of ∆ABC.

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