Q. 5 C5.0( 1 Vote )

# Let us draw the squares whose areas equal to the areas of the following triangles:An equilateral triangle whose side is 6cm. in length.

Steps of construction:

1) Draw a triangle PQR with sides PQ = QR = PR = 6 cm. 2) Draw a rectangle ARCP with area equal to that of triangle PQR, by choosing length of rectangle as half of base and height same as height of triangle.

[Here, area of rectangle = length × breadth

= 1/2 × base × height

= area of triangle]

Now, we can make a square with area equal to that of rectangle and hence equal to area of triangle. 3) Extend CP to CE, such that CE = BC 4) Draw the perpendicular bisector of PE which bisects PE at O. 5) Taking O as center and OD = OE as radius, draw a semicircle. 6) Extend BC which intersects semicircle at F. 7) Draw a square CFGH taking CF as side. Here,

Area of square CFGH = area of rectangle ABCD

= area of ΔPQR

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Nature of Roots of Quadratic Equations51 mins  Quiz | Criterion of Similarity of Triangle45 mins  Quiz on Number of Solutions of an Equation24 mins  Sum of n Terms of an AP36 mins  Geometry of Temples36 mins  Crystallization of Water31 mins  The Dimensions of Poverty81 mins  Transversal and Parallel Lines38 mins  Importance of Competitive Exams46 mins  Importance of Bases40 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 