Q. 5 B4.2( 6 Votes )

# Let’s find the G.

factors of 3y2-15y + 18

=3y2-9y-6y + 18

=3y(y-3)-6(y-3)

=(3y-6) (y-3)

=3(y-2) (y-3)

Factors of 2y2 + 2y-24

=2(y2 + y-12)

=2(y2 + 4y-3y-12)

=2(y(y + 4)-3(y + 4))

=2(y-3)(y + 4)

Factors of 4y2 + 36y + 80

=4(y2 + 9y + 20)

=4(y2 + 5y + 4y + 20)

=4{y(y + 5) + 4(y + 5)}

=4(y + 5)(y + 4)

LCM is the lowest common multiple, which is the product of all the common factors taken once and the remaining factors as it is.

the LCM of 3y2-15y + 18, 2y2 + 2y-24, 4y2 + 36y + 80 is 12(y-2)(y + 5)(y + 4)(y-3)

GCD is the greatest common divisor, which is equal to the product of all the common divisors.

the GCD is 1 as no other factor is common.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Let's find L.C.M.West Bengal - Mathematics

Let's find the L.West Bengal - Mathematics

Let’s solve the eWest Bengal - Mathematics

Let’s solve the eWest Bengal - Mathematics

Let’s find the L.West Bengal - Mathematics

Let’s find the L.West Bengal - Mathematics

Let’s find the L.West Bengal - Mathematics

Let’s solve the eWest Bengal - Mathematics

Let’s solve the eWest Bengal - Mathematics

Let’s find the L.West Bengal - Mathematics