Q. 5 A

# <span lang="EN-US

Given - Δ ABC is a triangle Ad is exterior bisector of A and meets BC at D

To prove -

Construction: Draw CEAD to meet AB at E

Proof -

In Δ ABC, CE AD cut by AC

CAD = ACE - - - alternate angles

In ΔABC CE

In Δ ABC, CE AD cut by AB

FAD = AEC - - - corresponding angles

∴∠ACE = AEC

AC = AE—isosceles triangle

In Δ BAD, CE DA

AE = DC

AB = BD

But AC = AE

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