Q. 5 A5.0( 1 Vote )

# Attempt any two o

The given situation is in A.P where n = 10, S10 = 4500 and common difference = - 10

We know that

4500 = 5[2a - 90]

2a – 90 = 900

2a = 990

a = 495

Also, an = a + (n - 1) × d where an is the nth term of A.P.

a10 = 495 + (10 - 1) × (- 10)

a10 = 495 - 90

a10 = 405

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