Q. 5 A5.0( 1 Vote )

Attempt any two o

Answer :

The given situation is in A.P where n = 10, S10 = 4500 and common difference = - 10

We know that



4500 = 5[2a - 90]


2a – 90 = 900


2a = 990


a = 495


Also, an = a + (n - 1) × d where an is the nth term of A.P.


a10 = 495 + (10 - 1) × (- 10)


a10 = 495 - 90


a10 = 405


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