Q. 594.0( 1 Vote )

# <span lang="EN-US

P(A) = 0.6 , P(B) = 0.2 , P = 0.5 (Given)   (1) = 1 – 0.2

= 0.8

Also,  = 1 – P(AB) (3)

Using (2) & (3) in Equation (1) we get, (3)

Now, P(AB) = 0.5 P(B) From (Given)

P(AB) = 0.5 0.2

P(AB) = 0.1

According to the addition theorem of probability,

P(AB) = P(A) + P(B) – P(AB)

= 0.6 + 0.2 – 0.1

= 0.8 – 0.1

= 0.7 (4)

Putting (4) in equation (3) we get,   Rate this question :

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