Answer :

Given,





Let tanx=t



Sec2x dx=dt


Now,



Now,


1 A(t-2)+B(2t+1)


Equating ‘t’ coeff: -


0=A+2B


A=-2B


Equating constant: -


1=-2A+B


1=-2(-2B) +B


1=5B


B=




Now,




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