Match the followi

A)

The man starts from A, goes east 10m to B. From B, he goes 20m to C.

AC² = AB² + BC²

AC² = 10² + 20²

AC² = 100 + 400 = 500

AC = √ 500 = 10√5

Therefore, (A)-(R)

B)

In ΔABD,

AB² = AD² + BD²

10² = AD² + 5²

AD² = 100-25 = 75

AD = √ 75 = 5√3

Therefore, (B)-(Q)

C)

Area of an equilateral triangle = cm

Therefore,(C)-(P)

D)

In ΔABC,

AC² = AB² + BC²

AC² = 6² + 8²

AD² = 36 + 64 = 100

AD = √ 100 = 10

Therefore, (D)-(S)