Q. 545.0( 2 Votes )

Match the followi

Answer :

A)


The man starts from A, goes east 10m to B. From B, he goes 20m to C.


AC2 = AB2 + BC2


AC2 = 102 + 202


AC2 = 100 + 400 = 500


AC = √ 500 = 10√5


Therefore, (A)-(R)


B)



In ΔABD,


AB2 = AD2 + BD2


102 = AD2 + 52


AD2 = 100-25 = 75


AD = √ 75 = 5√3


Therefore, (B)-(Q)


C)


Area of an equilateral triangle = cm


Therefore,(C)-(P)


D)



In ΔABC,


AC2 = AB2 + BC2


AC2 = 62 + 82


AD2 = 36 + 64 = 100


AD = √ 100 = 10


Therefore, (D)-(S)


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