# The sides BC, BA and CA of ΔABC have been produced to D, E and F respectively, as shown in the given figure. Then, ∠B = ?A. 35oB. 55oC. 65oD. 75o

BAC = 35o (opposite pair of angles)

BCD = 180 – 110 = 70o (linear pair of angles)

Now, in Triangle ABC we have,

A + B + C = 180o

35 + B + 70 = 180

B = 180 – 105 = 75o

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