Q. 514.0( 6 Votes )

# In figure, *p *is a transversal to lines *m *and *n*, ∠1 = 60° and Ð 2 = of a right angle. Prove that *m *|| *n*.

Answer :

∠1 = 60° (Given)

∠1 = ∠3(Vertically opposite angles)

∠2 = of a right angle (Given)

= × 90° = 60° ∴ ∠2 = ∠3

Since ∠2 and ∠3 are a pair of corresponding angles which are equal,

∠1 = ∠3(Vertically opposite angles)

∠2 = of a right angle (Given)

= × 90° = 60° ∴ ∠2 = ∠3

Since ∠2 and ∠3 are a pair of corresponding angles which are equal,

*m*||*n*.Rate this question :

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