Q. 51

Mark the correct alternative in each of the following:

A box contains 3 orange balls, 3 green balls and 2 blue balls. Three balls are drawn at random from the box without replacement. The probability of drawing 2 green balls and one blue balls is

A. 167/168

B. 1/28

C. 2/21

D. 3/28

Answer :

P(G) = Probability of drawing a green ball =


P(B) = Probability of drawing a blue ball =


P(O) = Probability of drawing an orange ball =


Important When taking the probability of green/ball in 2nd draw, remember to reduce the total number of balls and number of green/blue ball


While finding the probability. Example – P(GGB) =


Now Probability of drawing 2 green balls and one blue ball :


P = P(GGB) + P(GBG) + P(BGG)




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