# Write the sum of intercepts cut off by the plane on the three axes.[CBSE 2016]

The given equation when written in Cartesian form becomes

2x + y - z - 5 = 0

2x + y - z = 5

Divide throughout by 5 we get

x intercept = a = 5/2

y intercept = b = 1/5

z intercept = c = - 1/5

a + b + c =

Sum of intercepts = 5/2.

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