Answer :

|x – 1| ≤ 3

-3 ≤ x – 1 ≤ 3


-2 ≤ x ≤ 4


|x – 1 | ≤ 1


-1 ≤ x – 1 ≤ 1


0 ≤ x ≤ 2


We have to take intersection of x [-2, 4] and x [0, 2]


So, final answer is x [0, 2]


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